Dynamicke nasobeni matic – C / C++ – Fórum – Programujte.com

Zdravim tento program me funguje na ctvercove matice, kdyz zadam ale treba matici

A:

 1  -1

 2   0

-3  4



B:

1  2

3  4

#include <stdio.h>

#include <stdlib.h>



double **vytvor(int,int);

void nastav(int *,int *,char);

void smazat(double **,int);

double **nacti(double **,int, int,char);

double **soucin(double **,double **,int,int, int);

void vypis(double **,int,int,char);



int main()

{

	int ax,ay,bx,by,cx,cy;

	int n;

	double **a,**b,**c;

	

	nastav(&ax,&ay,'A');

	nastav(&bx,&by,'B');



	if(ay == bx)

	{

		n = ay;

		cx = ax;

		cy = by;

	}

	else

	{

		printf("!!! Pocet sloupcu matice A se musi rovnat poctu radkum matice B\n");

		return 1;

	}

	a = vytvor(ax,ay);

	b = vytvor(bx,by);

	

	nacti(a,ax,ay,'A');

	nacti(b,bx,by,'B');

	

	c = soucin(a,b,n,cx,cy);



	vypis(c,cx,cy,'C');

	

	smazat(a,ay);

	smazat(b,by);

	smazat(c,cy);



	return 0;

}



double **vytvor(int x,int y)

{

	double **mat;

	int i;

	mat = (double**)malloc(x * sizeof(double *));

	for(i = 0;i < y; i++)

		mat[i] = (double*)malloc(y * sizeof(double));

	return mat;

}



void nastav(int *x,int *y,char nazev)

{

	printf("Zadej pocet radku matice %c: ",nazev);

	scanf("%d",x);

	printf("Zadej pocet sloupcu matice %c: ",nazev);

	scanf("%d",y);

}



void smazat(double **mat,int y)

{

	int i;

	for(i = 0;i < y; i++)

		free(mat[i]);

	free(mat);

}



double **nacti(double **mat,int x, int y,char nazev)

{

	int i,j;

	printf("Zadej matici %c o rozmeru %d x %d:\n",nazev,x,y);

	for(i = 0;i < x;i++)

	{

		for(j = 0;j < y;j++)

		{

			printf("A[%d][%d] = ",i+1,j+1);

			scanf("%lf",&mat[i][j]);

		}

		printf("\n");

	}

	return vytvor(x,y);

}



double **soucin(double **a,double **b,int n,int x, int y)

{

	double **c;

	c = vytvor(x,y);

	int i,j,k;

	for(i = 0;i < x;i++)

		for(j = 0;j < n;j++)

		{

			c[i][j] = 0;

			for(k = 0;k < n;k++)

				c[i][j] = c[i][j] + a[i][k] * b[k][j];

		}

	return c;

}



void vypis(double **mat,int x,int y,char nazev)

{

	int i,j;

	printf("Matice %c:\n",nazev);

	for(i = 0;i < x;i++)

	{

		for(j = 0;j < y;j++)

			printf("%5.2lf   ",nazev,i+1,j+1,mat[i][j]);

		printf("\n");

	}	

}

Tak chyba nalezena na radku 53 ma byt x namisto y

for(i = 0;i < x; i++)