Sablona triedy a parameter s ukazovatelom – C / C++ – Fórum – Programujte.com

Zdravim,

mam problem s nasledujucim kodom:

queuetp.h

template <class T, int n>

class QueueTP

{

	private:

		struct Node

		{

			T item;

			Node * next;

		};

		

		Node * front;

		Node * rear;

		int items;

		const int qsize;



		QueueTP(const QueueTP & q) : qsize(0) {}

		QueueTP & operator=(const QueueTP & q) {return * this;}



	public:

		explicit QueueTP();

		~QueueTP();

		bool isempty() const;

		bool isfull() const;

		int queuecount() const;

		bool enqueue(const T & item);

		bool dequeue(T & item);

};



template <class T, int n>

QueueTP<T, n>::QueueTP() : qsize(n)

{

	front = rear = NULL;

	items = 0;

}



template <class T, int n>

QueueTP<T, n>::~QueueTP()

{

	Node * temp;



	while (front != NULL)

	{

		temp = front;

		front = temp->next;

		delete temp;

	}

}



template <class T, int n>

bool QueueTP<T, n>::isempty() const

{

	return items == 0;

}



template <class T, int n>

bool QueueTP<T, n>::isfull() const

{

	return items == qsize;

}



template <class T, int n>

int QueueTP<T, n>::queuecount() const

{

	return items;

}



template <class T, int n>

bool QueueTP<T, n>::enqueue(const T & item)

{

	if (isfull())

		return false;

	

	Node * add = new Node;



	if (add == NULL)

		return false;

	

	add->item = item;

	add->next = NULL;

	items++;



	if (front == NULL)

		front = add;

	else

		rear->next = add;

	

	rear = add;



	return true;

}



template <class T, int n>

bool QueueTP<T, n>::dequeue(T & item)

{

	if (front == NULL)

		return false;

	

	item = front->item;

	items--;

	Node * temp = front;

	front = front->next;



	delete temp;



	if (items == 0)

		rear = NULL;

	

	return true;

}

#include <iostream>

#include <cstring>

using namespace std;



class Worker

{

	private:

		char * fullName;

		int id;

	

	public:

		Worker(const char * fn = "no name", const int n = 0);

		Worker(const Worker & w);

		~Worker();

		Worker & operator=(const Worker & w);

		void Show() const;

};



Worker::Worker(const char * fn, const int n)

{

	fullName = new char[strlen(fn) + 1];

	strcpy(fullName, fn);

	id = n;

}



Worker::Worker(const Worker & w)

{

	fullName = new char[strlen(w.fullName) + 1];

	strcpy(fullName, w.fullName);

	id = w.id;

}



Worker::~Worker()

{

	delete [] fullName;

}



Worker & Worker::operator=(const Worker & w)

{

	if (this == &w)

		return *this;

	

	delete [] fullName;

	fullName = new char[strlen(w.fullName) + 1];

	strcpy(fullName, w.fullName);

}



void Worker::Show() const

{

	cout << "Meno pracovnika: " << fullName << endl

		<< "ID pracovnika: " << id << endl;

}

#include <iostream>

#include "queuetp.h"

#include "wrkr.h"



const int SIZE = 4;

const int AR_SIZE = 20;



int main()

{

	QueueTP<Worker*, SIZE> workers; // ak by som tu dal parameter hodnotu (tj. len Worker) tak to funguje ale nechapem preco ma problem s ukazovatelom

	

	char choice;

	

	for (int i = 0; i < SIZE; i++)

	{

		cout << "p: pridat pracovnika, o: odobrat pracovnika, k: koniec\n";

		char choice;

		cin >> choice;



		if (choice == 'k') break;

		

		while (strchr("pok", choice) == NULL)

		{

			cout << "Zadajte p, o alebo k: ";

			cin >> choice;

		}

		

		cin.get();



		switch (choice)

		{

			case 'p':

				{

					char name[AR_SIZE];

					int id;



					cout << "Meno pracovinka: ";

					cin.getline(name, AR_SIZE);

					cout << "ID pracovnika: ";

					cin >> id;

					

					workers.enqueue(Worker(name, id));



					break;

				}

			case 'o':

				Worker temp;

				workers.dequeue(temp);

				temp.Show();



				break;

		}

	}



	return 0;

}

taktiez mi v Worker & Worker::operator=(const Worker & w) chyba return *this; ale to na vysledku taktiez nic nemeni

QueueTP je deklarovaná takto: template <class T, int n> class QueueTP

Takže při instanciaci šablony QueueTP<Worker*, SIZE> bude za T dosazen typ Worker*.

Metoda enqueue je deklarována jako bool enqueue(const T & item);, po instanciaci šablony to tedy bude
bool enqueue(const Worker* & item);

Této metodě předáváš ale Worker. Proto to nejde.

ondra.holub dakujem ^_^. vsetko krasne funguje (no...to co hadzalo errory este opravit tie ostatne veci ale hlavne ze toto ide)...ja som bol v tom ze pri pouziti sablony sa (de)referencny operator (*/&) odhadzuje a zostane mi cisty nazov typu s ktorym si uz mozem robit co chcem ale mylil som sa. este raz diky