Pointer nebo reference na property - jak ji získat? – C / C++ – Fórum – Programujte.com

Ahoj,

potřebuji aby funkce za svého běhu změnila obsah property komponenty TChart.  Jak předám funkci ukazatel nebo referenci na tuto property? jedná se konkrétně o Fmain->Chart1->LeftAxis->Minimum

hu

Lepší asi bude předat funkci Chart1 a až tam přistupovat k té property.

Páč používat odkazy na property by se ti asi nemuselo líbit

class X {
public:
  int a;
  void f(int b) {
    cout << "The value of b is "<< b << endl;
  }
};

int main() {

  int X::*ptiptr = &X::a;
  void (X::* ptfptr) (int) = &X::f;
  X xobject;
  xobject.*ptiptr = 10;

  cout << "The value of pointer is " << xobject.*ptiptr << endl;
  cout << "The value of property is " << xobject.a << endl;

  (xobject.*ptfptr) (20);
}

Pokud by jsme ale zvolnili pravidla pointerů tak, aby nemusely vždy ukazovat na property tříd:

#include <iostream>
using namespace std;
class Y
{
public:
	int o;

};


class X {
public:
  int a;
  Y objY;
  void f(int b) {
    cout << "The value of b is "<< b << endl;
  }
};

template<class T>
void ok(T *p)
{
	*p=88;
}

void ko(int *ptiptr)
{
	*ptiptr=78;
}



int main() {

  // declare pointer to data member
  int X::*ptiptr = &X::a;

  // declare a pointer to member function
  void (X::* ptfptr) (int) = &X::f;

  // create an object of class type X
  X xobject;
  int *lo = &xobject.a;
  *lo=10;
  cout << "The value of pointer is " << xobject.a << endl;
  ok(&xobject.objY.o);
  cout << "The value of pointer is " << xobject.objY.o << endl;
  ko(&xobject.objY.o);
  cout << "The value of pointer is " <<xobject.objY.o << endl;

  // initialize data member
  xobject.*ptiptr = 10;

  cout << "The value of pointer is " << xobject.*ptiptr << endl;
  cout << "The value of property is " << xobject.a << endl;

  // call member function
  (xobject.*ptfptr) (20);
}