Guestbook s sql a problem s netypickou captchou :)

Guestbook s sql a problem s netypickou captchou :)

Návštěvník

3. 3. 2009 #1

Cafte, tak svoj e book chrsanim trochu netypicky :)

Zo zadaneho mena vygenerujem md5 hash ktory sa ukaze userovi, po zadani do dalsieho inputu a odoslani by mal dalej pokracovat skript tj odoslat spravu... Zatial to vsak mam iba tak ze by sa malovypisat OK alebo chyba cez if a else, nieco natom vsak nefunguje....

Chybu nepise ziadnu....



<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" 

                      "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">



<html xmlns="http://www.w3.org/1999/xhtml">

<head>

<meta http-equiv="content-type" content="text/html; charset=utf-8" />

<title>Simple GuestBook</title>

<link href="style.css" rel="stylesheet" type="text/css" media="screen" />

<style type="text/css">

a {text-decoration: none; color: green;}

a:hover {text-decoration: underline; color: silver; position: relative; margin-left: auto; margin-right: auto;}

body{background-color: #020202; color: #f2f2f2;}

</style>

</head>

<body>

<center><a href="#" onClick="document.getElementById('forms').style.display='block'">Pridať príspevok</a>

<div id="forms" style="display: none">

<form method="POST" action="index.php">

Meno:   <input type="text" name="autor" />

Správa: <textarea name="text" cols="50" rows="10" /></textarea>

<input type="submit" />

</form>

</div>

</center>

<?php

/*

 CREATE TABLE `gb`.`g_book` (

`id` INT NOT NULL AUTO_INCREMENT ,

`autor` TINYTEXT CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL ,

`text` TINYTEXT CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL ,

`ip` TINYTEXT NOT NULL ,

PRIMARY KEY ( `id` )

) ENGINE = MYISAM CHARACTER SET utf8 COLLATE utf8_unicode_ci 

*/



$autor = htmlspecialchars($_POST['autor']);

$text = htmlspecialchars($_POST['text']);



$pripoj = mysql_connect("localhost", "root", "0000") or die(mysql_error());

mysql_select_db("gb");

$trimmed =trim($_POST['autor']);

$trimmed1 =trim($_POST['text']);

if(!empty($trimmed) and $trimmed1){

$captcha = $_POST['meno'];

$captcha2 = md5($captcha);

echo $captcha2;

echo "<form method='POST'>

      <input type='text' name='a'>

      <input type='button'>

      </form>";

$porovnaj = $_POST['a'];

 if($porovnaj === $captcha2){

echo "ok";}

else{echo "chyba";}

$sql = mysql_query("INSERT INTO g_book(autor, text) VALUES('$autor', '$text')");

if($sql){

echo "<center>Správa odoslaná.</center>";



 }

}

else{echo "<center>Nemôžete odoslať prázdnu správu.</center>";}

$sql = mysql_query("SELECT * FROM g_book ORDER BY id DESC");

while($vypis = mysql_fetch_array($sql)){

?>









<?php

include ('wrap.php');

echo "<b>" . $vypis['autor'] . "</b>" . "" . "  " . $vypis['text'] . "</div>"; }

?>









</body>

</html>

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Super člen

4. 3. 2009 #2

vo - if($porovnaj === $captcha2) - ako predpokladam chces skontrolovat ci sa $porovnaj rovna $captcha2, no lenze, mas tam tri rovna sa(=) preto ti to zrejme nejde.. musis iba dve =

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