Anonymní profil Karolina – Programujte.com

#8 hlucheucho
ok, princip asi chapu, to jsem tedy zmenila. diky oboum.

#5 hlucheucho
to tam mam ;-)

#include <stdio.h>
#include <limits.h>
#include <float.h>

int main()

{

...

return 0;

}

#3 KIIV
 printf("Please enter the number of triangles to check: \n");
  scanf("%d", &pocet_trojuhelniku);

Pocet trojuhelniku urci uzivatel.

#1 Karolina
ajaj, misto anzahl_d ma byt pocet_trojuhelniku (chtela jsem to zmenit pro potreby ceskeho fora, no par jsem jich prehledla) :-))

Ahoj vsem, 

nebyl by tu nekdo tak hodny a pomohl mi s ukolem? V programovani jsem relativni zacatecnik a obavam se, ze tohle zadani je nad moje sily a chapani. Domnivam se, ze to ma byt sestrojene jako array[pocet_trojuhelniku][3].

1. Uzivatel ma byt vyzvan k zadani cisla (mnozstvi kontrolovanych trojuhelniku, >= 1, < UCHAR_MAX, musi to byt integer). To, myslim, mam v poradku.

int pocet_trojuhelniku;
int check = 0;
char letter_check;
float trojuhelnik[pocet_trojuhelniku][3];

do
{
  printf("Please enter the number of triangles to check: \n");
  scanf("%d", &anzahl_d);
  scanf("%c", &letter_check);

  if(letter_check != '\n')
  {
    while(getchar() != '\n')
    {
    }
    check = 0;
  }

  if(anzahl_d >= 1 && anzahl_d < UCHAR_MAX)
  {
    check = 1;
  }
  if(pocet_trojuhelniku < 1 || pocet_trojuhelniku > UCHAR_MAX)
  {
    printf("[ERR] Invalid number of triangles.\n");
    check = 0;
  }
}
while(check == 0);

2. Uzivatel ma byt pocet_trojuhelniku-krat vyzvan k zadani velikosti stran ( > 0.0, < FLT_MAX, musi to byt float). A tady uz mam problemy s kontrolou, zda je vse zadano v poradku.

int counter;

for(counter = 0; counter < anzahl_d; counter++)
{
  printf("Please enter the first number of the triplet: \n");
  scanf("%f", &dreieck[counter][0]);

  printf("Please enter the second number of the triplet: \n");
  scanf("%f", &dreieck[counter][1]);

  printf("Please enter the third number of the triplet: \n");
  scanf("%f", &dreieck[counter][2]);
}

Kdyz jsem se snazila uplatnit vyse uvedene do, if, while, tak mi chodila hlaska "Segmenation fault".

A dal uz jsem uplne ztracena....

3. Razeni kazde trojice cisel (velikosti stran) od nejmensiho po nejvetsi. (bubble sort?)

4. Na zaklade a+b>c, a+c>b, b+c>a ma byt urceno, zda se jedna o trojuhelnik. Vystup ma vypadat takto: Triplet [number] (a=[a], b=[b], c=[c]) is a triangle. (prip. is NO triangle).

5. Pro kazdou trojici ma byt urceno, zda se jedna o rovnostranny trojuhelnik (a==b && b==c), rovnoramenny trojuhelnik (a==b || b==c || a==c), pripadne pravouhly trojuhelnik (a*a + b*b == c*c || b*b + c*c == a*a || a*a + c*c == b*b).

Body cislo 4 a 5 se mi podarilo vyresit pouze pro pripad propoctu jednohoh trojuhelniku, nevim, jak to nasadit na pole.

if((a + b) > c)
{
  if((a + c) > b)
  {
    if((b + c) > a)
    {
      printf("Triplet (a=%f, b=%f, c=%f) is a triangle.\n", a, b, c);
    }
  }
}

else
{
  printf("Triplet (a=%f, b=%f, c=%f) is no triangle.\n", a, b, c);
}

if(a==b && b==c)
{
  printf("It is an equilateral triangle.\n");
}

if(a==b || b==c || a==c)
{
  printf("It is an isosceles triangle.\n");
}

if(a*a + b*b == c*c || b*b + c*c == a*a || a*a + c*c == b*b)
{
  printf("It is a right triangle.\n");
}
 

6. Pokud by melo po jakemkoli inputu nasledovat EOF, ma byt program bez dalsiho ukoncen.
 

Ukazka, jak to ma vypadat:

Please enter the number of triangles to check: 0

[ERR] Invalid number of triangles.

Please enter the number of triangles to check: 4

Please enter the first number of the triplet: 1

Please enter the second number of the triplet: 2

Please enter the third number of the triplet: foo

[ERR] Invalid number for the triplet.

Please enter the third number of the triplet: 1

Please enter the first number of the triplet: 4.5

Please enter the second number of the triplet: 7.24

Please enter the third number of the triplet: 4.5

Please enter the first number of the triplet: 11.7

Please enter the second number of the triplet: 11.7

Please enter the third number of the triplet: 11.7

Please enter the first number of the triplet: 3

Please enter the second number of the triplet: 4

Please enter the third number of the triplet: 5

Triplet 1 (a=1.000000, b=1.000000, c=2.000000) is NO triangle.

Triplet 2 (a=4.500000, b=4.500000, c=7.240000) is a triangle.

It is an isosceles triangle.

Triplet 3 (a=11.700000, b=11.700000, c=11.700000) is a triangle.

It is an equilateral triangle.

It is an isosceles triangle.

Triplet 4 (a=3.000000, b=4.000000, c=5.000000) is a triangle.

It is a right triangle.

Budu vdecna za jakoukoli pomoc....